NDA2017MathematicsFunctionsActual
Let f( x ): cases x , & x is rational 0, & x is irrational cases and g ( x ): cases 0, & x is rational x , & x is irrational cases If f: R R and g : R R , then (f- g ) is
Options
- Aone-one and into
- Bneither one-one nor onto
- Cmany-one and onto
- Done-one and onto
Correct answer
D. one-one and onto
Step-by-step solution
(f-g)(x)= array c x-0=x, x is rational 0-x=-x, x is irrational array . Clearly, f - g is one - one and onto.