NDA 2017
- Exam
- NDA
- Year
- 2017
- Subject
- Mathematics
- Chapter
- Functions
NDA 2017 · Mathematics · Functions
Let f(x): cases x, & x is rational 0, & x is irrational cases and...
Let \begin{cases}\mathrm{x}, & \mathrm{x} \text{ is rational } \\ 0, & \mathrm{x} \text{ is irrational }\end{cases}and
$\mathrm{g}(\mathrm{x}): $\begin{cases}0, & \mathrm{x} \text{ is rational } \\ \mathrm{x}, & \mathrm{x} \text{ is irrational }\end{cases}
If and , then is
Options
- Aone-one and into
- Bneither one-one nor onto
- Cmany-one and onto
- Done-one and onto
Correct answer
D. one-one and onto
Step-by-step solution
(f-g)(x)=\left\{\right.
Clearly,