NDA2017MathematicsFunctionsActual
Let f( x )= px + q and g ( x )= mx + n . Then f( ~g ( x ))= g (f( x )) is equivalent to
Options
- Af( p )= g ( m )
- Bf( q )= g ( n )
- Cf( n )= g ( q )
- Df( ~m )= g ( p )
Correct answer
C. f( n )= g ( q )
Step-by-step solution
aligned & f ( x )= px + q , g ( x )= mx + n & f ( g ( x ))= g ( f ( x )) & f ( mx + n )= g ( px + q ) & p ( mx + n )+ q = m ( px + q )+ n & pmx + pn + q = pmx + mq + n & pn + q = mq + n & f ( n )= g ( q ) aligned