NDA 2022
- Exam
- NDA
- Year
- 2022
- Subject
- Mathematics
- Chapter
- Limits
NDA 2022 · Mathematics · Limits
What is _ x arrow 0 x 1- ^4 x equal to?
What is
limx→01−cos4xx equal to?
Options
- A221
- B−221
- C2
- DLimit does not exist
Correct answer
D. Limit does not exist
Step-by-step solution
x→0lim1−cos4xx=x→0lim2∣sin2x∣2x×21 L.H.L =−221 and R.H.L. =221∵ L.H.L = R.H.L.
So,
limx→0f(x) is not exist.
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