The magnetic energy stored in an inductor of inductance 4μ H carrying a current of 2A is:

Correct answer: A. 8μ J Magnetic energy stored in an inductor is given by, U = (1)/(2)L i ^ 2 = (1)/(2) × (4 × 10 ^ - 6 ) × 2 ^ 2 = 8 × 10 ^ - 6 J = 8μ J

NEET 2023

Exam: NEET
Year: 2023
Subject: Physics
Chapter: Electromagnetic Induction

NEET 2023 · Physics · Electromagnetic Induction

The magnetic energy stored in an inductor of inductance 4μ H...

The magnetic energy stored in an inductor of inductance

4\mu H

carrying a current of

2A

is:

Options

A $8\mu J$
B $4\mu J$
C $4mJ$
D $8mJ$

Correct answer

A. $8\mu J$

Step-by-step solution

Magnetic energy stored in an inductor is given by,
$U = \dfrac{1}{2}L{i}^{2} = \dfrac{1}{2} \times \left(4 \times {10}^{- 6}\right) \times {2}^{2} = 8 \times {10}^{- 6}J = 8\mu J$

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