NEET2023PhysicsElectromagnetic InductionActual
The magnetic energy stored in an inductor of inductance 4   μH carrying a current of 2   A is:
Options
- A8   μJ
- B4   μJ
- C4   mJ
- D8   mJ
Correct answer
A. 8   μJ
Step-by-step solution
Magnetic energy stored in an inductor is given by, U = 1 2 L i 2 = 1 2 × 4 × 10 - 6 × 2 2 = 8 × 10 - 6   J = 8   μJ