Two identical inductors are connected in two different configurations P and Q, where a time varying current I(t) is flowing, as shown in the figure. The induced emf between points a and b for configuration P is E_P and that for configuration Q is E_Q . The ratio E_P/E_Q is : [Neglect the effect of mutual inductance.]

Step-by-step solution

Let the inductance of each identical inductor be L . For configuration (P): The two inductors are connected in series. The points a and b are located across the first inductor only. The current flowing through this inductor is I(t) . The induced emf between points a and b is given by: E_P = L dI dt For configuration (Q): The two inductors are connected in parallel. The points a and b are the common nodes of this parallel combination. The equivalent inductance L_ eq between a and b is: L_ eq = L L L + L = L 2 The to