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NEET 2019
Exam
NEET
Year
2019
Subject
Physics
Chapter
Electromagnetic Induction

NEET 2019 · Physics · Electromagnetic Induction

A 800 turn coil of the effective area 0.05 m ^ 2 is kept...

A 800800 turn coil of the effective area 0.05m20.05{m}^{2} is kept perpendicular to the magnetic field 5×10−5T.5 \times {10}^{- 5}T . When the plane of the coil is rotated by 90o{90}^{o} around any of its coplanar axis in 0.1s,0.1s, the emf induced in the coil will be:

Options

  1. A2V2V
  2. B0.2V0.2V
  3. C2×10−3V2 \times {10}^{- 3}V
  4. D0.02V0.02V

Correct answer

D. 0.02V0.02V

Step-by-step solution

By Faraday's law, induced EMF in coil is equal to rate of change of magnetic flux linked with coil so

ε=−∆ϕ∆t=−ϕf−ϕi∆t=−0−NBA∆tε = - \dfrac{∆ ϕ}{∆ t}= - \dfrac{{ϕ}_{f} - {ϕ}_{i}}{∆ t}= - \dfrac{0 - NBA}{∆ t}
=800×5×10−5×0.050.1= \dfrac{800 \times 5 \times {10}^{- 5} \times 0.05}{0.1}
~ & =0.02V= 0.02V

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