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NEET2026PhysicsSemiconductorsActual

The current I in the circuit shown below is : (All diodes are ideal and identical)

Options

  1. A5 3 A
  2. B5 9 A
  3. C1 3 A
  4. D15 2 A

Correct answer

D. 15 2 A

Step-by-step solution

From the given circuit, the positive terminal of the 10 V battery is connected to the left side of the parallel branches. Therefore, the left side is at a higher potential compared to the right side. The diodes in the branches with 4 and 2 resistors have their anodes connected to the higher potential side, so they are forward-biased and act as short circuits (since they are ideal). The diodes in the branches with 3 and 5 resistors have their cathodes connected to the higher potential side, so they are reverse-biase

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