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NTA Abhyas JEE Main2020ChemistryClassification of Elements and Periodicity in PropertiesPractice

The values of electronegativity of atom A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A - B bond is nearly

Correct answer

72.24

Step-by-step solution

% ionic character of a bond is determined with the help of Hanny-Smith's equation. % ionic characters =1 .6 ( ΔEN ) +3 .5 ( ΔEN ) 2 Where, ΔEN = difference of electronegativity = 4 .0 − 1 .2 = 2 .80 So, % ionic character =1 .6 ( 2 .80 ) +3 .5 ( 2 .80 ) 2 = 72.24 %

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