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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Classification of Elements and Periodicity in Properties

NTA Abhyas 2020 · Chemistry · Classification of Elements and Periodicity in Properties

The values of electronegativity of atom A and B are 1.20 and 4.0...

The values of electronegativity of atom A\text{A} and B\text{B} are 1.20 and 4.0 respectively. The percentage of ionic character of A−B\text{A} - \text{B} bond is nearly

Correct answer

72.24

Step-by-step solution

% ionic character of a bond is determined with the help of Hanny-Smith's equation.

% ionic characters =1.6(\DeltaEN)+3.5(\DeltaEN)2\text{=1}\text{.6}( \text{\Delta EN} )\text{+3}\text{.5}{( \text{\Delta EN} )}^{\text{2}}

Where, \DeltaEN\text{\Delta EN}= difference of electronegativity =

4.0−1.2 = 2.80\text{4}\text{.0} - \text{1}\text{.2 = 2}\text{.80}

So, % ionic character =1.6(2.80)+3.5(2.80)2=72.24\text{=1}\text{.6}( \text{2}\text{.80} )\text{+3}\text{.5}{( \text{2}\text{.80} )}^{\text{2}} = 72.24%
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