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NTA Abhyas JEE Main2020ChemistryClassification of Elements and Periodicity in PropertiesPractice

The atomic numbers of vanadium V , chromium Cr , manganese Mn and iron (Fe) are respectively 23, 24, 25 and 26 . Which one of these may be expected to have the highest second ionization enthalpy?

Options

  1. AMn
  2. BV
  3. CCr
  4. DFe

Correct answer

C. Cr

Step-by-step solution

Consider Electronic configuration of M + 23 V + ⇒ 18 [Ar] 4s 1 3d 3 24 Cr + ⇒ 18 [Ar] 4s 0 3d 5 25 Mn + ⇒ 18 [Ar] 4s 1 3d 5 26 Fe + ⇒ 18 [Ar]   3d 6   4s 1 Removal of second electron from stable configuration of 18 [Ar] 4s 0 3d 5 will require very high energy input i.e. (Cr) as it will disturb the stable electronic configuration of 3d 5 (half filled subshell).

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