NTA Abhyas JEE Main2020ChemistryClassification of Elements and Periodicity in PropertiesPractice
If the dipole moment of AB molecule is given by 1.2 D and A-B the bond length is 1 Å then % ionic character of the bond is [Given: 1debye = 10 − 18 esu . cm ]
Options
- A75
- B50
- C60
- D25
Correct answer
D. 25
Step-by-step solution
μ C a l = 4.8 × 1 0 - 10 e . s . u × 1 0 - 8 c m = 4.8 × 1 0 - 18 e s u c m = 4 . 8 D Hence % ionic character = μ experimental μ calculated × 100 = 1.2 4.8 × 100 = 25 %