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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Classification of Elements and Periodicity in Properties

NTA Abhyas 2020 · Chemistry · Classification of Elements and Periodicity in Properties

If the dipole moment of AB molecule is given by 1.2 D and A-B the...

If the dipole moment of AB molecule is given by 1.2 D and A-B the bond length is 1Å1\text{Å} then % ionic character of the bond is
[Given: 1debye =10−18esu.cm\text{1debye =}{10}^{- 18} \text{esu}\text{.}\text{cm}]

Options

  1. A75
  2. B50
  3. C60
  4. D25

Correct answer

D. 25

Step-by-step solution

μCal=4.8×10−10e.s.u×10−8cm{\mu}_{Cal} = 4.8 \times 1{0}^{- 10}e. s. u \times 1{0}^{- 8}cm

=4.8×10−18esucm= 4.8 \times 1{0}^{- 18}esucm

=4.8 D= 4. \text{8 D}

Hence \text{% ionic character} = \dfrac{{μ}_{\text{experimental}}}{{μ}_{\text{calculated}}} \times 100
= \dfrac{1.2}{4.8} \times 100 = 25\text{%}
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