NTA Abhyas JEE Main2020ChemistryClassification of Elements and Periodicity in PropertiesPractice
Which of the following order is correct for the property mentioned in brackets?
Options
- AS 2 - > C l - > K + > C a 2 + (Ionization energy)
- BC < N < F < O (2nd Ionization energy)
- CB > A l > G a > I n > T l (Electronegativity)
- DN a + > L i + > M g 3 + > B e 2 + > A l 3 + (Ionic radius)
Correct answer
B. C < N < F < O (2nd Ionization energy)
Step-by-step solution
A. Correct order → C a 2 + > K + > C l - > S 2 - (ionization energy) for isoelectronic species (I.E. ∝ Z e f f ) B. Correct order → C < N < F < O (2nd I.E.) Second electron removal from oxygen requires more energy as it acquires stable 2 s 2 2 p 3 configuration after removal of one electron. C. → B > T l > I n > G a > A l (Electronegativity) In general EN increases in boron family from top to bottom due to increase in Z e f f on valence shell while boron has highest E.N. due to its vary small size. D. Correct order