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The total number of possible isomers for the complex compound C u N H 3 4 [ P t C l 4 ]

Options

  1. A4
  2. B5
  3. C6
  4. D3

Correct answer

A. 4

Step-by-step solution

1. C u N H 3 4 [ P t C l 4 ] 2. C u N H 3 3 C l [ P t C l 3 ( N H 3 ) ] 3*. Cu NH 3 2 Cl 2 PtCl 2 NH 3 2 - cis isomer 4*. Cu NH 3 2 Cl 2 PtCl 2 NH 3 2 - trans isomer 5. C u N H 3 C l 3 [ P t ( C l ) ( N H 3 ) 3 ] 6, P t N H 3 4 [ C u C l 4 ] * These isomers would not exist as charge on the cation & anion would be zero.

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