NTA Abhyas JEE Main2020ChemistryCoordination CompoundsPractice
Nickel (Z = 28) combines with a uninegative monodentate ligand to form a diamagnetic complex NiL 4 2 − . The hybridisation involved and the number of unpaired electrons present in the complex are respectively:
Options
- Adsp 2 , zero
- Bsp 3 , zero
- Cdsp 2 , , one
- Dsp 3 , two
Correct answer
A. dsp 2 , zero
Step-by-step solution
28 Ni has +2 oxidation state and since the complex is Diamagnetic, all electrons are paired in inner 3d, orbital to provide the electronic configuration as under: L − might have been a strong field like CN − . Hybridisation is dsp 2 . Number of unpaired electrons = 0