NTA Abhyas JEE Main2020ChemistryCoordination CompoundsPractice
A complex of molecular formula C r C l 3 . 6 H 2 O has green colour 0.1 mole of the complex when treated with excess of A g N O 3 gave 28.7 g of white precipitate of AgCl (Molar mass = 143.5 g). The formula of the complex would be
Options
- A[ C r ( H 2 O ) 6 ] C l 3
- B[ C r C l ( H 2 O ) 5 ] C l 2 . H 2 O
- C[ C r C l 2 ( H 2 O ) 4 ] C l . 2 H 2 O
- D[ C r ( H 2 O ) 3 C l 3 ] 3 H 2 O
Correct answer
B. [ C r C l ( H 2 O ) 5 ] C l 2 . H 2 O
Step-by-step solution
C r C l 3 . 6 H 2 O 0.1 m o l + A g N O 3 e x c e s s → A g C l 28.7 g No. of moles of A g C l = 28.7 143.5 ≈ 0.2 m o l Hence it required 2 mole free Cl atom.