Two complexes [ Cr H 2 O ) 6 C l 3 A and [ Cr N H 3 ) 6 C l 3 B are violet and yellow coloured, respectively. The incorrect statement regarding them is:

Step-by-step solution

H 2 O is weaker ligand than N H 3 So, ( Δ 0 ) B > ( Δ 0 ) A Since, oxidation number of C r in the complex Cr ( H 2 O ) 6 x0 - 1 C l 3 is calculated as, x + 6 0 + 3 ( - 1 ) = 0 = x = + 3 So, C r 3 + has 3 d 3 configuration Similarly, oxidation no. of C r in Cr ( N H 3 ) 6 x0 - 1 C l 3 is calculated as, x + 6 ( 0 ) + 3 ( - 1 ) = 0 = x = + 3 So C r 3 + has 3 d 3 configuration Thus, both A and B are paramagnetic with 3 unpaired electrons. We know, Δ = h c λ absorbed Since ( Δ 0 ) B > ( Δ 0 ) A λ A > λ B A is violet col