NTA Abhyas JEE Main2020ChemistryCoordination CompoundsPractice
Each of the compounds P t N H 3 6 C l 4 , C r N H 3 6 C l 3 , C o N H 3 4 C l 3 and K 2 PtCl 6 were dissolved in water to make its 0.01 M solution. The correct order of their increasing conductivity in solution is
Options
- AK 2 P t C l 6 < C o N H 3 4 · C l 3 < C r N H 3 6 C l 3 < P t N H 3 6 C l 4
- BC r N H 3 6 C l 3 < C o N H 3 4 · C l 3 < K 2 P t C l 6 < P t N H 3 6 C l 4
- CC o N H 3 4 · C l 3 < K 2 P t C l 6 < C r N H 3 6 C l 3 < P t N H 3 6 C l 4
- DP t N H 3 6 C l 4 < C o N H 3 6 · C l 3 < C r N H 3 6 C l 3 < K 2 P t C l 6
Correct answer
C. C o N H 3 4 · C l 3 < K 2 P t C l 6 < C r N H 3 6 C l 3 < P t N H 3 6 C l 4
Step-by-step solution
In aqueous solution 0 .001 M , then complexes with dissociate to give the ions : [Pt ( NH 3 ) 6 Cl 4 ] ⇌ [ Pt ( NH 3 ) 6 ] 4+ + 4Cl − ; 5 ions [Cr(NH 3 ) 6 ]Cl 3 ⇌ [ Cr ( NH 3 ) 6 ] 3+ + 3Cl − ; 4 ions [Co(NH 3 ) 4 Cl 2 ]Cl ⇌ [Co(NH 3 ) 4 Cl 2 ] + + Cl - ; 2 ions K 2 [PtCl 6 ] ⇌ PtCl 6 2 − +2K +   ;   3   ions