NTA Abhyas JEE Main2020ChemistryCoordination CompoundsPractice
Arrange the following cyano complexes in decreasing order of their magnetic moment.
Options
- A[ C r ( C N ) 6 ] 3 - > [ M n ( C N ) 6 ] 3 - > [ F e ( C N ) 6 ] 3 - > [ C o ( C N ) 6 ] 3 -
- B[ M n ( C N ) 6 ] 3 - > [ C r ( C N ) 6 ] 3 - > [ F e ( C N ) 6 ] 3 - > [ C o ( C N ) 6 ] 3 -
- C[ F e ( C N ) 6 ] 3 - > [ C r ( C N ) 6 ] 3 - > [ M n ( C N ) 6 ] 3 - > [ C o ( C N ) 6 ] 3 -
- D[ C o ( C N ) 6 ] 3 - > [ C r ( C N ) 6 ] 3 - > [ M n ( C N ) 6 ] 3 - > [ F e ( C N ) 6 ] 3 -
Correct answer
A. [ C r ( C N ) 6 ] 3 - > [ M n ( C N ) 6 ] 3 - > [ F e ( C N ) 6 ] 3 - > [ C o ( C N ) 6 ] 3 -
Step-by-step solution
[ C r ( C N ) 6 ] 3 - C r 3 + in strong ligand field = t 2 g 3 e g 0 = 3 unpaired electron [ M n ( C N ) 6 ] 3 - M n 3 + in strong ligand field = t 2 g 4 e g 0 = 2 unpaired electron [ F e ( C N ) 6 ] 3 - F e 3 + in strong ligand field = t 2 g 5 e g 0 = 1 unpaired electron [ C o ( C N ) 6 ] 3 - C o 3 + in strong ligand field = t 2 g 6 e g 0 = 0 unpaired electron