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The correct hybridization of F e in complex K 3 [Fe(CN) 6 ] is

Options

  1. Ad s p 3
  2. Bs p 3
  3. Cs p 3 d 2
  4. Dd 2 s p 3

Correct answer

D. d 2 s p 3

Step-by-step solution

K 3 [ F e ( C N ) 6 ] Electronic configuration of F e = [ A r ] 4 s 2 3 d 6 Electronic configuration of F e + 3 = [ A r ] 3 d 5 Number of ligand (coordination numbr) = 6 Nature of ligand is strong field. Hybridization of F e is d 2 s p 3 .

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