NTA Abhyas JEE Main2020ChemistryCoordination CompoundsPractice
Match the following: Column – I Column - II A. sp 3 (i) Co NH 3 6 3+ B. dsp 2 (ii) Ni CO 4 C. sp 3 d 2 (iii) Pt NH 3 2 Cl 2 D. d 2 sp 3 (iv) CoF 6 3 −
Options
- AA B C D (v) (ii) (iv) (iii)
- BA B C D (ii) (iii) (iv) (v)
- CA B C D (ii) (iii) (i) (v)
- DA B C D (ii) (iii) (iv) (i)
Correct answer
D. A B C D (ii) (iii) (iv) (i)
Step-by-step solution
I. [Co(NH 3 ) 6 ] 3+ Here Co is present as Co 3+ ion. NH 3 being strong field ligand pair up the unpaired electrons of Co . 27 Co = Ar 3d 7 4s 2 ∴ Co 3+ = Ar 3d 6 4s 0 II. Ni CO 4 Here Ni is present in its ground state. CO being a strong field ligand, pair up the unpaired electrons of Ni 28 Ni = Ar 3d 8 4s 2 III. Pt NH 3 2 Cl 2 Here Pt is present as Pt 2+ ion. 78 Pt = Xe 5d 9 6s 1 Pt 2+ = Xe 5d 8 6s 0 IV. CoF 6 3 − Here Co is present as Co 3+ ion, F being weak field ligand is unable to pair up its unpaired electron