NTA Abhyas JEE Main2020Chemistryp Block Elements (Group 13 & 14)Practice
Identify X and Y in the following reaction BCl 3 + NH 4 Cl → 140 o C / C 6 H 5 Cl X → NaBH 4 Y
Options
- AX = N a B O 2 , Y = B 2 O 3
- BX = N a 2 B 4 O 7 , Y = H 3 B O 3
- CX = B N , Y = N H 4 + B C l 4 -
- DX = B 3 N 3 H 3 C l 3 , Y = B 3 N 3 H 6
Correct answer
D. X = B 3 N 3 H 3 C l 3 , Y = B 3 N 3 H 6
Step-by-step solution
3   BCl 3   +   3   NH 4 Cl → 140 o C   /   C 6 H 5 Cl B 3 N 3 H 3 Cl 3 X → NaBH 4 B 3 N 3 H 6 Borazine Y