Identify X and Y in the following reaction BCl _ 3 + NH _ 4 Cl 140 ^ o C/ C _ 6 H _ 5 Cl → X NaBH _ 4 → Y

Correct answer: D. X = B _ 3 N _ 3 H _ 3 C l _ 3 , Y = B _ 3 N _ 3 H _ 6 3 BCl _ 3 +3 NH _ 4 Cl 140 ^ o C/ C _ 6 H _ 5 Cl → B _ 3 N _ 3 H _ 3 Cl _ 3 _ (X) NaBH _ 4 → B _ 3 N _ 3 H _ 6 _ (Borazine) _ (Y)

NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Chemistry
Chapter: p Block Elements (Group 13 & 14)

NTA Abhyas 2020 · Chemistry · p Block Elements (Group 13 & 14)

Identify X and Y in the following reaction BCl _ 3 + NH _ 4 Cl 140...

Identify X and Y in the following reaction

{\text{BCl}}_{\text{3}} \text{+}{\text{NH}}_{\text{4}} \text{Cl}\overset{{\text{140}}^{\text{o}} \text{C}\text{/}{\text{C}}_{\text{6}} {\text{H}}_{\text{5}} \text{Cl}}{\to} \text{X}\overset{{\text{NaBH}}_{\text{4}}}{\to} \text{Y}

Options

A $X = NaB{O}_{2}, Y = {B}_{2}{O}_{3}$
B $X = N{a}_{2}{B}_{4}{O}_{7}, Y = {H}_{3}B{O}_{3}$
C $X = BN, Y = {\left[N{H}_{4}\right]}$ ^{+}{ $\left[BC{l}_{4}\right]}^{-}$
D $X = {B}_{3}{N}_{3}{H}_{3}C{l}_{3}, Y = {B}_{3}{N}_{3}{H}_{6}$

Correct answer

D. $X = {B}_{3}{N}_{3}{H}_{3}C{l}_{3}, Y = {B}_{3}{N}_{3}{H}_{6}$

Step-by-step solution

\text{3}{\text{BCl}}_{\text{3}} \text{+}\text{3}{\text{NH}}_{\text{4}} \text{Cl}\overset{{\text{140}}^{\text{o}} \text{C}\text{/}{\text{C}}_{\text{6}} {\text{H}}_{\text{5}} \text{Cl}}{\to} \mathop{{\text{B}}_{\text{3}} {\text{N}}_{\text{3}} {\text{H}}_{\text{3}} {\text{Cl}}_{\text{3}}}_{\left(\text{X}\right)} \overset{{\text{NaBH}}_{\text{4}}}{\to} \mathop{{\text{B}}_{\text{3}} {\text{N}}_{\text{3}} {\text{H}}_{\text{6}}}_{\mathop{\left(\text{Borazine}\right)}_{\left(\text{Y}\right)}}

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