Compound (X) on reduction with LiAl H _ 4 gives a hydride (Y)...

Compound (X) on reduction with

LiAl{H}_{4}

gives a hydride (Y) containing 21.72% hydrogen along with other products. The compound (Y) reacts with air explosively resulting in boron trioxide. Compounds x and Y are respectively

Options

A $BC{l}_{3}, {B}_{2}{H}_{6}$
B ${B}_{2}{H}_{6}, BC{l}_{3}$
C $B{F}_{3}, A{l}_{2}{O}_{6}$
D ${B}_{2}{H}_{6}, B{F}_{3}$

Correct answer

A. $BC{l}_{3}, {B}_{2}{H}_{6}$

Step-by-step solution

\mathop{4BC{l}_{3}}_{\left(X\right)} + 3LiAl{H}_{4} \to \mathop{2{B}_{2}{H}_{6}}_{\left(Y\right)} + 3AlC{l}_{3} + 3LiCl

Percentage of hydrogen in

{B}_{2}{H}_{6} = \dfrac{6}{27.62} \times 100 = 21.72

{B}_{2}{H}_{6} + 3{O}_{2}\overset{Explosion}{→}{B}_{2}{O}_{3} + 3{H}_{2}O

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