NTA Abhyas JEE Main2020Chemistryp Block Elements (Group 13 & 14)Practice
In the following series of reactions: i A + 2 HCl + 5 H 2 O ⟶ 2 NaCl + X ii X ⟶ 3 7 0 K Δ H BO 2 ⟶ Red heat Δ Z iii 4 BF 3 + 3 LiAlH 4 ⟶ Y + 3 LiF + 3 AlF 3 The compounds A, X, Z and Y may be selected from following options
Options
- AA X Z Y Na 2 B 4 O 7 H 3 BO 3 B 2 O 3 B 2 H 6
- BA X Z Y H 3 BO 3 Na 2 B 4 O 7 B 2 H 6 B 2 O 3
- CA X Z Y B 2 H 6 B 2 O 3 H 3 BO 3 Na 2 B 4 O 7
- DA X Z Y B 2 O 3 H 2 B O 3 Na 2 B 4 O 7 B 2 H 6
Correct answer
A. A X Z Y Na 2 B 4 O 7 H 3 BO 3 B 2 O 3 B 2 H 6
Step-by-step solution
Na 2 B 4 O 7 + 2 HCl + 5 H 2 O ⟶ 2 NaCl + 4 H 3 BO 3 Borax (A) Orthoboric aicd (X) H 3 BO 3 ⟶ Δ , 3 7 0 K HBO 2 + H 2 O X Metaboric acid 4 HBO 2 → Δ , Red heat 2 B 2 O 3 Boron trioxide z + H 2 O 4BF 3 + 3LiAlH 4 → 2B 2 H 6 (Diborane) + 3LiF + 3AlF 3