In the following series of reactions: (i) cases A + 2 HCl + 5 H _ 2 O & ⟶ & 2 NaCl + X cases (ii) cases X & ⟶ _ 370K ^ Δ & H BO _ 2 & ⟶ _ Red~heat ^ Δ & Z cases (iii) cases 4 BF _ 3 + 3 LiAlH _ 4 & ⟶ & Y + 3 LiF + 3 AlF

Correct answer: A. cases A & & X & & Z & & Y Na _ 2 B _ 4 O _ 7 & & H _ 3 BO _ 3 & & B _ 2 O _ 3 & & B _ 2 H _ 6 cases cases Na _ 2 B _ 4 O _ 7 & + 2 HCl + 5 H _ 2 O & ⟶ & 2 NaCl & + & 4 H _ 3 BO _ 3 Borax (A) & & & & & Orthoboric aicd (X) cases cases H _ 3 BO _ 3 & Δ , 3 7 0 K ⟶ & HBO _ 2 & + & H _ 2 O (X) & & Metaboric acid & & cases 4 HBO _ 2 Δ, Redheat → 2 B _ 2 O _ 3 array ll Borontrioxide (z) array + H _ 2 O 4BF _ 3 + 3LiAlH _ 4 → 2B _ 2 H _ 6 _ (Diborane) +3LiF+ 3AlF _ 3

NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Chemistry
Chapter: p Block Elements (Group 13 & 14)

NTA Abhyas 2020 · Chemistry · p Block Elements (Group 13 & 14)

In the following series of reactions: (i) cases A + 2 HCl + 5 H _ 2...

In the following series of reactions:

\left(\text{i}\right)

\begin{cases}\text{A} + 2 \text{HCl} + 5 {H}_{2} \text{O} & ⟶ & 2 \text{NaCl} + \text{X}\end{cases}

<br /> <br /> \left(\text{ii}\right)$\begin{cases}\text{X} & \mathop{⟶}_{370\text{K}}^{Δ} & \text{H}{BO}_{2} & \mathop{⟶}_{Red~heat}^{Δ} & \text{Z}\end{cases}

\left(\text{iii}\right)

\begin{cases}4 {BF}_{3} + 3 {LiAlH}_{4} & ⟶ & \text{Y} + 3 \text{LiF} + 3 {AlF}_{3}\end{cases}

$

The compounds A, X, Z and Y may be selected from following options

Options

A $\begin{cases}\text{A} & & \text{X} & & \text{Z} & & \text{Y} \\ {Na}_{2} {B}_{4} {O}_{7} & & {H}_{3} {BO}_{3} & & {B}_{2} {O}_{3} & & {B}_{2} {H}_{6}\end{cases}$
B $\begin{cases}\text{A} & & \text{X} & & \text{Z} & & \text{Y} \\ {H}_{3} {BO}_{3} & & {Na}_{2} {B}_{4} {O}_{7} & & {B}_{2} {H}_{6} & & {B}_{2} {O}_{3}\end{cases}$
C $\begin{cases}\text{A} & & \text{X} & & \text{Z} & & \text{Y} \\ {B}_{2} {H}_{6} & & {B}_{2} {O}_{3} & & {H}_{3} {BO}_{3} & & {Na}_{2} {B}_{4} {O}_{7}\end{cases}$
D $\begin{cases}\text{A} & & \text{X} & & \text{Z} & & \text{Y} \\ {B}_{2} {O}_{3} & & {H}_{2} {\text{B} \text{O}_{3} & & {Na}_{2} {B}_{4} {O}_{7} & & {B}_{2} {H}_{6}\end{cases}$

Correct answer

A. $\begin{cases}\text{A} & & \text{X} & & \text{Z} & & \text{Y} \\ {Na}_{2} {B}_{4} {O}_{7} & & {H}_{3} {BO}_{3} & & {B}_{2} {O}_{3} & & {B}_{2} {H}_{6}\end{cases}$

Step-by-step solution

\begin{cases}{Na}_{2} {B}_{4} {O}_{7} & + 2 \text{HCl} + 5 {H}_{2} \text{O} & ⟶ & 2 \text{NaCl} & + & 4 {H}_{3} {BO}_{3} \\ \text{Borax (A)} & & & & & \text{Orthoboric aicd (X)}\end{cases}

\begin{cases}{H}_{3} {BO}_{3} & \overset{\Delta \text{,} 3 7 0 \text{K}}{⟶} & {HBO}_{2} & + & {H}_{2} \text{O} \\ \left(\text{X}\right) & & \text{Metaboric acid} & & \end{cases}

4{HBO}_{2}\overset{\Delta, Redheat}{→}2{B}_{2}{O}_{3}

\begin{array}{ll}Borontrioxide \\ \left(z\right)\end{array}

+ {H}_{2}O

{4BF}_{3}\text{+}{3LiAlH}_{4} \to \mathop{{2B}_{2}{H}_{6}}_{(Diborane)}\text{+}\text{3LiF}\text{+}{3AlF}_{3}

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