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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Practical Chemistry

NTA Abhyas 2020 · Chemistry · Practical Chemistry

Gradual addition of potassium iodide solution to aqueous Bi (N O _...

Gradual addition of potassium iodide solution to aqueous Bi(NO3)Bi{\left(N{O}_{3}\right)}_{3}solutioninitiallyproducesadarkbrownprecipitatewhichdissolvesinexcessofsolution initially produces a dark brown precipitate which dissolves in excess ofKI to give a clear yellow solution. Identify the yellow precipitate.

Options

  1. AI2{I}_{2}
  2. BKI3K{I}_{3}
  3. CBi{\left(OH\right)}_{2}
  4. DBiBi\left(OH\right){\left(N{O}_{3}\right)}_{2}

Correct answer

B. KI3K{I}_{3}

Step-by-step solution

At first Bi(NO3)Bi{\left(N{O}_{3}\right)}_{3}undergoeshydrolysis.<br/><br/>Nitricacidisformedwhichoxidisesundergoes hydrolysis.<br /><br />Nitric acid is formed which oxidisesI^{−} to iodine. The liberated iodine dissolves in KK to form yellow precipitate of KI3{KI}_{3}.

Bi(NO3)3+H2O→[Bi(OH)(NO3)2]+HNO3Bi{\left(N{O}_{3}\right)}_{3} + {H}_{2}O \to \left[Bi\left(OH\right){ \left(N{O}_{3}\right)}_{2}\right] + HN{O}_{3}

2HNO3→H2O+2NO2+[O]2HN{O}_{3} \to {H}_{2}O + 2N{O}_{2} + \left[O\right]

2KI+H2O+[O]→2KOH+I2Darkbrown2KI + {H}_{2}O + \left[O\right] \to 2KOH + \mathop{I2}_{Darkbrown}

I2+KI→KI3yellowsolution{I}_{2} + KI \to \mathop{K{I}_{3}}_{yellowsolution}
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