NTA Abhyas JEE Main2020ChemistrySolid StatePractice
Calculate the density (in k g m - 3 ) of potassium hving a b c c structure with nearest neighbour distance of 4.52 Å . (Given atomic weight of potassium is 39)
Correct answer
910
Step-by-step solution
For bcc, d = 3 2 a Or a = 2 d 3 = 2 × 4.52 1.732 = 5.219 A ∘ = 522 p m ρ = Z × M a 3 × N 0 × 1 0 - 30 = 2 × 39 ( 522 ) 3 × ( 6.023 × 1 0 23 ) × 1 0 - 30 = 0.91 g / c m 3 = 910 k g m - 3