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In a cubic packed structure of mixed oxides, the lattice is made up of oxide ions, one fifth of tetrahedral voids one occupied by X ions while one half of the octahedral voids are occupied by Y ions. Then formula of the oxide will be

Options

  1. AX 5 Y 4 O 10
  2. BX 4 Y 5 O 10
  3. CX Y 2 O 4
  4. DX 2 Y O 4

Correct answer

B. X 4 Y 5 O 10

Step-by-step solution

Number of O 2 - ions = n Number of tetrahedral voids = 2n Number of octahedral voids = n Number of X ions = 2 n 5 Number of Y ions = n 2 X   :   Y   :   O 2n 5   :   n 2   :   n 4   :   5   :   10 Simplest formula = X 4 Y 5 O 10 .

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