_ x → 0 (1 + x) x^ 2 + (x - 1)/(x) =

$\lim_{x \to 0} \dfrac{\ln\left(1 + x\right) + x^{2} - x}{x2}$

using expansion, we know,

$\ln\left(1 + x\right) = x - \dfrac{x^{2}}{2} + \dfrac{x^{3}}{3} \ldots \ldots$

$⇒ \dfrac{\lim_{x \to 0} x - \dfrac{x2}{2} +.... + x^{2} - x}{x2}$

$= \dfrac{1}{2}$