NTA Abhyas JEE Main2020MathematicsLimitsPractice
The value of lim x → π tan ( π cos 2 x ) sin 2 x is equal to
Options
- A1
- Bπ
- C- π
- Dπ 2
Correct answer
C. - π
Step-by-step solution
Let, x = π + t lim t → 0 tan π cos 2 ( π + t ) sin 2 ( π + t ) ⇒ lim t → 0 tan ( π cos 2 t ) sin 2 t lim t → 0 tan π − π sin 2 t sin 2 t ⇒ lim t → 0 − tan ( π sin 2 t ) π sin 2 t · π = − π