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NTA Abhyas JEE Main2020MathematicsLimitsPractice

The value of l i m x → 0 - 2 1 x + 2 3 x 3 2 1 x + 5 2 3 x is

Options

  1. A1 3
  2. B1 5
  3. C1
  4. D1 4

Correct answer

A. 1 3

Step-by-step solution

l i m x → 0 - 2 1 x 1 + 2 2 x 2 1 x 3 + 5 ⋅ 2 2 x ⇒ l i m x → 0 - 1 + 2 1 x 3 + 5 2 2 x = 1 + 0 3 + 0 = 1 3

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