NTA Abhyas JEE Main2020MathematicsLimitsPractice
The value of l i m x → 0 t a n 2 3 x 5 - 4 + s e c x is equal to
Options
- A2 5
- B- 9 5
- C9 5
- D- 36 5
Correct answer
D. - 36 5
Step-by-step solution
After rationalization, l i m x → 0 t a n 2 3 x 5 + 4 + s e c x 5 - 4 + sec ⁡ x ⇒ l i m x → 0 t a n 2 3 x 9 x 2 ⋅ 9 x 2 c o s x - 1 5 + 4 + 1 ⇒ 9 - 2 2 5 = - 36 5