NTA Abhyas JEE Main2020MathematicsLimitsPractice

The value of l i m x → 1 - π - 4 t a n - 1 x 1 - x is equal to

Options

A2 π
B1 2 π
C4 π
D0

Correct answer

D. 0

Step-by-step solution

After rationalization l i m x → 1 - π - 4 t a n - 1 x 1 - x π + 4 t a n - 1 x = 1 2 π l i m x → 1 - π - 4 t a n - 1 x 1 - x By L-hospital rule, we get, 1 2 π l i m x → 1 - - 4 1 + x 2 - 1 2 1 - x = 4 π l i m x → 1 - 1 - x 1 + x 2 = 0

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