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Basics of Mathematics — BITSAT Mathematics PYQs

12 previous year questions from Basics of Mathematics with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

12 questionsMathematicsSolutions on every page
1

If n is a positive integer, then 2.4^ 2 n+1 +3^ 3 n+1 is divisible by:

BITSAT 2023 Solution View → 2

The solution set of (x-2)^ x^3-6 x+8 >1 is

BITSAT 2023 Solution View → 3

If x, y and z are real numbers, the x²+4 y²+9 z²-6 y z-3 z x-2 x y is always

BITSAT 2020 Solution View → 4

If x = log 5 3 + log 7 5 + log 9 7 , then

BITSAT 2019 Solution View → 5

If a = log 2 3 , b = log 2 5 and c = log 7 2 , then log 140 63 in terms of a , b , c is

BITSAT 2017 Solution View → 6

The value of 2 1 ! + 2 + 4 2 ! + 2 + 4 + 6 3 ! + … . is

BITSAT 2017 Solution View → 7

2^ 3 n -7 n-1 is divisible by

BITSAT 2014 Solution View → 8

The greatest positive integer, which divides n ( n +1)( n +2)( n +3) for all n N , is

BITSAT 2014 Solution View → 9

The set of all real x satisfying the inequality 3-|x| 4-|x| 0, is

BITSAT 2013 Solution View → 10

If x satisfies |3 x-2|+|3 x-4|+|3 x-6| 12 , then

BITSAT 2013 Solution View → 11

Let x and y be two natural numbers such that x y=12(x+y) and x y . Then the total number of pairs (x, y) is

BITSAT 2012 Solution View → 12

Prabhat wants to invest the total amount of Rs 15,000 in saving certificates and national saving bonds. According to rules, he has to invest at least Rs 2000 in saving certificates

BITSAT 2012 Solution View →
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