An equilateral triangular loop A D C of uniform specific resistivity having some resistance is pulled with a constant velocity v out of a uniform magnetic field directed into the paper. At time t = 0 , side D C of the loop is at the edge of the magnetic field. The induced current I versus time t graph will be as :

Step-by-step solution

Let 2 a be the side of the triangle and b the length A E . ∆ AHG and ∆ AEC are similar triangles. A H A E = G H E C ∴ G H = A H A E E C = b - v t b . a = a - a b v t ∴ F G = 2 G H = 2 a - a b v t Induced e.m.f., e = B v F G = 2 B v a - a b v t ∴ Induced current, I = e R = 2 B v R a - a b v t or I = k 1 - k 2 t Thus, the I - t graph is a straight line with a negative slope and positive intercept.