NEET
- Exam
- NEET
- Subject
- Physics
- Chapter
- Electromagnetic Induction
NEET · Physics · Electromagnetic Induction
A metallic ring of mass m and radius l (ring being horizontal) is...
A metallic ring of mass m and radius l (ring being horizontal) is falling under gravity in a region having a magnetic field. If z is the vertical direction, the z-component of magnetic field is Bz= Bo(1+λ z). If R is the resistance of the ring and if the ring falls with a velocity v, find the energy lost in the resistance. If the ring has reached a constant velocity, use the conservation of energy to determine v in terms of m, B, λ and acceleration due to gravity g.
Options
- A\frac{mgR}{9{{\left( \pi {{l}^{2}}\lambda {{B}_{o}} \right)}^{2}}}
- B\frac{mgR}{4{{\left( \pi {{l}^{2}}\lambda {{B}_{o}} \right)}^{2}}}
- C\frac{mgR}{16{{\left( \pi {{l}^{2}}\lambda {{B}_{o}} \right)}^{2}}}
- D\frac{mgR}{{{\left( \pi {{l}^{2}}\lambda {{B}_{o}} \right)}^{2}}}
Correct answer
D. \frac{mgR}{{{\left( \pi {{l}^{2}}\lambda {{B}_{o}} \right)}^{2}}}
Step-by-step solution
Correct Option is : (D)
$\frac{mgR}{{{\left( \pi {{l}^{2}}\lambda {{B}_{o}} \right)}^{2}}}
$\frac{mgR}{{{\left( \pi {{l}^{2}}\lambda {{B}_{o}} \right)}^{2}}}