AIIMS2009PhysicsElectromagnetic Induction
A coil of wire of a certain radius has 100 turns and a self inductance of 15 mH . The self inductance of a second similar coil of 500 turns will be
Options
- A75 mH
- B375 mH
- C15 mH
- Dnone of these
Correct answer
B. 375 mH
Step-by-step solution
Inductance of a coil is given by aligned & L= 1 2 ₀ N^2 R L₂ L₁ = N₂^2 N₁^2 & L₂=L₁ N₂^2 N₁^2 = ( 500 100 )^2 15 mH =375 mH aligned