Let f(x)= (x⁵-1 ) (x³+1 ), g(x)= (x²-1 ) (x²-x+1 ) and let h ( x ) be such that f ( x )= g ( x ) h ( x ) . Then limh _ x 1 ~h ( x ) is

Step-by-step solution

Given f(x)=g(x) h(x) h(x)= f(x) g(x) _ x 1 h(x)= _ x 1 f(x) g(x) _ x 1 (x⁵-1 ) (x³+1 ) (x²-1 ) (x²-x+1 ) = _ x 1 x⁵-1⁵ x-1 =5 1⁴=5