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BITSAT 2013

Exam: BITSAT
Year: 2013
Subject: Mathematics
Chapter: Limits

BITSAT 2013 · Mathematics · Limits

If f(x)=\ array cl x^ 2 +3 x-10 x^ 2 +2 x-15 & , when x ≠-5 a , &...

If

f(x)=\left\{

\begin{array}{cl}\frac{x^{2}+3 x-10}{x^{2}+2 x-15} & \text{ , when } x \neq-5 \\ \text{ a }, & \text{ when } x=-5\end{array}

\right.

is continuous at

x=-5

, then the value of 'a' will be

Options

A $3 / 2$
B $7 / 8$
C $8 / 7$
D $2 / 3$

Correct answer

B. $7 / 8$

Step-by-step solution

\lim _{x \rightarrow-5} f(x)=\frac{(x-2)(x+5)}{(x+5)(x-3)}=\frac{-7}{-8}=\frac{7}{8}

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