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BITSAT 2010
Exam
BITSAT
Year
2010
Subject
Mathematics
Chapter
Limits

BITSAT 2010 · Mathematics · Limits

Find the equation of chord of the circle x²+y²=8 x bisected at the...

Find the equation of chord of the circle x2+y2=8xx²+y²=8 x bisected at the point (4,3)(4,3)

Options

  1. Ay=3y=3
  2. By=1y=1
  3. Cy=6y=6
  4. Dy=7y=7

Correct answer

A. y=3y=3

Step-by-step solution

\begin{aligned}& \mathrm{T}=\mathrm{S} }_{1} \Rightarrow \mathrm{x}(4)+ \mathrm{y}(3)-4(\mathrm{x}+4)=16+9-32 \\ & \Rightarrow 3 \mathrm{y}-9=0 \Rightarrow \mathrm{y}=3 \end{aligned}
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