Two tangents (P Q ) and (P R ) drawn to the circle (x^2+y^2-2 x-4 y-20=0 ) from point (P(16,7) ). Ifthe centre of the circle is (C ) then the area of quadrilateral ( PQCR ) is

Step-by-step solution

Area ( PQCR =2~ ~ PQC =2 1 2 ~L r ) where ( L = ) length of tangent and (r= ) radius of circle. ( L = S ₁ =15 and r = 1+4+20 =5 ) Hence the required area (=75 ) sq. units.