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BITSAT 2009

Exam: BITSAT
Year: 2009
Subject: Mathematics
Chapter: Limits

BITSAT 2009 · Mathematics · Limits

Two tangents P Q and P R drawn to the circle x²+y²-2 x-4 y-20=0...

Two tangents

P Q

and

P R

drawn to the circle

x²+y²-2 x-4 y-20=0

from point

P(16,7)

. Ifthe centre of the circle is

C

then the area of quadrilateral (

\mathrm{PQCR}

) is

Two tangents P Q and P R drawn to the circle x²+y²-2 x-4 y-20=0 from point P(16,7) . Ifthe centre of the circle is C

Options

A75 sq. unit
B73 sq. unit
C72 sq. unit
D74 sq. unit

Correct answer

A. 75 sq. unit

Step-by-step solution

Area (

\mathrm{PQCR}=

2~ \triangle ~

\mathrm{PQC}=

2

\times \frac{1}{2} \mathrm{~L} \times

r)

Two tangents P Q and P R drawn to the circle x²+y²-2 x-4 y-20=0 from point P(16,7) . Ifthe centre of the circle is C

where (

\mathrm{L}=

length of tangent and

r=

radius of circle. (

\mathrm{L}=\sqrt{\mathrm{S}_1}=

15

\text{

and

} \mathrm{r}=\sqrt{1+4+20}=

5) Hence the required area

=75

sq. units.

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