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BITSAT 2020
Exam
BITSAT
Year
2020
Subject
Physics
Chapter
Laws of Motion

BITSAT 2020 · Physics · Laws of Motion

The coefficient of friction between the rubber tyres and the road...

The coefficient of friction between the rubber tyres and the road wayis 0.25.0.25 . The maximum speed with which a car can be driven round a curve of radius 20 m20 \mathrm{~m} without skidding is (g=9.8 m/\mathrms2)\left(\mathrm{g}=9.8 \mathrm{~m} / \mathrms^{2}\right)

Options

  1. A5m/s5 \mathrm{ m} / \mathrm{s}
  2. B7m/s7 \mathrm{ m} / \mathrm{s}
  3. C10m/s10 \mathrm{ m} / \mathrm{s}
  4. D14m/s14 \mathrm{ m} / \mathrm{s}

Correct answer

B. 7m/s7 \mathrm{ m} / \mathrm{s}

Step-by-step solution

μ\mu\mathrm{mg}=\mathrm{mv}2/r^{2} / \mathrm{r} or v=μgr\mathrm{v}=\sqrt{\mu \mathrm{g} \mathrm{r}} or v=(0.25×9.8×20)=7m/sv=\sqrt{(0.25 \times 9.8 \times 20)}=7 \mathrm{ m} / \mathrm{s}
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