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BITSAT 2020
Exam
BITSAT
Year
2020
Subject
Physics
Chapter
Laws of Motion

BITSAT 2020 · Physics · Laws of Motion

A body of mass 2 ~kg is placed on a horizontal surface having...

A body of mass 2 kg2 \mathrm{~kg} is placed on a horizontal surface having kinetic friction 0.4 and static friction 0.5.0.5 . If the force applied on the body is 2.5 N,2.5 \mathrm{~N}, then the frictional force acting on the body will be [g=10 ms−2]\left[\mathrm{g}=10 \mathrm{~ms}^{-2}\right]

Options

  1. A8N8 \mathrm{ N}
  2. B10N10 \mathrm{ N}
  3. C20N20 \mathrm{ N}
  4. D2.5N2.5 \mathrm{ N}

Correct answer

D. 2.5N2.5 \mathrm{ N}

Step-by-step solution

Limiting friction =0.5×2×10=10N=0.5 \times 2 \times 10=10 \mathrm{ N} The applied force is less than force of friction, therefore the force of friction is equal to the applied force.
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