The force on a body of mass 1 kg is 20 i ^ + 10 j ^ N . If it starts from rest, then the position of the body at time t = 2 s , is

Step-by-step solution

F = 20   i ^ + 10   j ^ ∴ F x = 20   N and F y = 10   N ∴ Acceleration, a x = F x m = 20 1 a x = 20   m   s - 2 and a y = F y m = 10 1 = 10   m   s - 2 ∴ Displacement of body in x -direction in 2   s . x = u x   t + 1 2 a x   t 2 = 0 + 1 2 × 20 × 2 2 = 40   m Displacement of body in y -direction in 2   s . y = u y   t + 1 2   a y   t 2 = 0 + 1 2 × 10 × 2 2 = 20   m ∴ Position of the body