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BITSAT 2017

Exam: BITSAT
Year: 2017
Subject: Physics
Chapter: Laws of Motion

BITSAT 2017 · Physics · Laws of Motion

A block A of mass 100 kg rests on another block B of mass 200 kg...

A block $A$ of mass $100$ kg rests on another block $B$ of mass $200$ kg and is tied to a wall as shown in the figure. The coefficient of friction between $A and B$ is $0 . 2 and that between$ B $and ground is$ 0 . 3 $. The minimum force required to move the block$ B $is \left(g = 10ms^{- 2}\right)$

A block A of mass 100 kg rests on another block B of mass 200 kg and is tied to a wall as shown in the figure. The

Options

A $900N$
B $200N$
C $1100N$
D $700N$

Correct answer

C. $1100N$

Step-by-step solution

Friction force between $A$ and $B$ and between block $B$ and surface $S$ will oppose $F$

$∴ F = {F}_{AB} + {F}_{BS} = {μ}_{AB}{M}_{A}g + {μ}_{BS}\left({m}_{A} + {m}_{B}\right)g$

$= 0. 2 \times 100 \times 10 + 0. 3\left(100 + 200\right) \times 10$

$= 200 + 900 = 1100N$

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