BITSAT2017PhysicsLaws of MotionActual
A block A of mass 100 kg rests on another block B of mass 200 kg and is tied to a wall as shown in the figure. The coefficient of friction between A and B is 0 . 2 and that between B and ground is 0 . 3 . The minimum force required to move the block B is g = 10 m s - 2
Options
- A900   N
- B200   N
- C1100   N
- D700   N
Correct answer
C. 1100   N
Step-by-step solution
Friction force between A and B and between block B and surface S will oppose F ∴   F = F A B + F B S = μ A B M A g + μ B S m A + m B g = 0 . 2 × 100 × 10 + 0 . 3 100 + 200 × 10 = 200 + 900 = 1100   N