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BITSAT2016PhysicsLaws of MotionActual

Block A of mass m and block B of mass 2 ~m are placed on a fixed triangular wedge by means of a massless, inextensible string and a frictionless pulley as shown in figure. The wedge is inclined at 45^ to the horizontal on both the sides. If the coefficient of friction between the block A and the wedge is 2 / 3 and that between the block B and the wedge is 1 / 3 and both the blocks A and B are released from rest, the

Options

  1. A-1 ~ms ⁻²
  2. B1.2 ~ms ⁻²
  3. C0.2 ~ms ⁻²
  4. Dzero

Correct answer

D. zero

Step-by-step solution

Total maximum friction force, (f_ t =f_ A +f_ B ) ( _ A mg 45^ + _ B 2 mg 45^ ) or, (f_ t =m g ( 2 3 1 2 + 1 3 2 1 2 ) ) (= 4 3 2 mg ) The net pulling force, (F=2 m g 45^ -m g 45^ ) (= mg 45^ ) (= m g 2 ) ( F < f _ t ) ( ) The blocks will not move. So, acceleration of block A is Zero. ( ) option (D) is correct.

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