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JEE Advanced2023ChemistryCoordination CompoundsActual

Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option. [Atomic Number: Fe = 26 , Mn = 25 , Co = 27 ] List I List II P t 2 g 6 e g 0 1 Fe H 2 O 6 2 + Q t 2 g 3 e g 2 2 Mn H 2 O 6 2 + R e 2 t 2 3 3 Co NH 3 6 3 + S t 2 g 4 e g 2 4 FeCl 4 - 5 CoCl 4 2 -

Options

  1. A  P   →   1 ;   Q   →   4 ;   R   →   2 ; &#160
  2. BP   →   1 ;   Q   →   2 ;   R   →   4 ;   S &#1
  3. CP   →   3 ;   Q   →   2 ;   R   →   5 ;   S &#1
  4. DP   →   3 ;   Q   →   2 ;   R   →   4 ;   S &#1

Correct answer

D. P   →   3 ;   Q   →   2 ;   R   →   4 ;   S &#1

Step-by-step solution

In the complex Fe H 2 O 6 2 + the electronic configuration of Fe 2 + is Ar 3 d 6 . H 2 O is a weak ligand. Hence, the crystal filed splitting can be shown as follows, In the complex Mn H 2 O 6 2 + the electronic configuration of Mn 2 + is Ar 3 d 5 . H 2 O is a weak ligand. Hence, the crystal filed splitting can be shown as follows, In the complex Co NH 3 6 3 + the electronic configuration of Fe 3 + is Ar 3 d 6 . NH 3 is a strong filed ligand. Hence, the crystal filed splitting can be shown as follows, In the comple

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