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JEE Main 202624 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
24 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Amines

JEE Main 2026 · 24 January · Evening Shift · Chemistry · Amines

Given below are two statements: Statement I : The dipole moment of...

Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce
Given below are two statements: Statement I : The dipole moment of R-CN is greater than R-NC and R-NC can undergo.
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with SOCl2\mathrm{SOCl}_{2}, followed by the addition of NH3\mathrm{NH}_{3} gives another compound (x)(\mathrm{x}). This compound (x)(\mathrm{x}) on treatment with NaOCl/NaOH\mathrm{NaOCl} / \mathrm{NaOH} gives a product, that on treatment with CHCl3/KOH/Δ\mathrm{CHCl}_{3} / \mathrm{KOH} / \Delta produces R-NC.
In the light of the above statements, choose the correct answer from the options given below

Options

  1. ABoth Statement I and Statement II are false
  2. BStatement I is false but Statement II is true
  3. CBoth Statement I and Statement II are true
  4. DStatement I is true but Statement II is false

Correct answer

B. Statement I is false but Statement II is true

Step-by-step solution

Statement I: The dipole moment of alkyl cyanides (R−CNR-CN) is indeed greater than alkyl isocyanides (R−NCR-NC) because the C≡NC \equiv N bond is more polar than the N+≡C−N^+ \equiv C^- bond where formal charges oppose the electronegativity difference. However, the acidic hydrolysis of R−NCR-NC produces a primary amine (R−NH2R-NH_2) and formic acid (HCOOHHCOOH), not a carboxylic acid (R−COOHR-COOH). Thus, Statement I is false.
Statement II: R−CNR-CN on acidic hydrolysis gives R−COOHR-COOH. Treatment with SOCl2SOCl_2 gives R−COClR-COCl. Addition of NH3NH_3 gives R−CONH2R-CONH_2 (compound x). Treatment of R−CONH2R-CONH_2 with NaOCl/NaOHNaOCl/NaOH (Hofmann Bromamide Degradation equivalent) gives R−NH2R-NH_2. R−NH2R-NH_2 on treatment with CHCl3/KOH/ΔCHCl_3/KOH/\Delta (Carbylamine reaction) produces R−NCR-NC. Thus, Statement II is true.
Therefore, Statement I is false but Statement II is true.
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