A hydrocarbon ' P ^ ( C ₄ H ₈ ) on reaction with HCl gives an optically active compound ' Q ' ( C ₄ H ₉ Cl ) which on reaction with one mole of ammonia gives compound ' R ^ ( C ₄ H ₁₁ ~N ) . ' R ^ on diazotization followed by hydrolysis giv

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A hydrocarbon ' P ^ ( C ₄ H ₈ ) on reaction with HCl gives an optically active compound ' Q ' ( C ₄ H ₉ Cl ) which on reaction with one mole of ammonia gives compound ' R ^ ( C ₄ H ₁₁ ~N ) . ' R ^ on diazotization followed by hydrolysis gives ' S '. Identify P , Q , R and S.

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Correct answer: 3

For Q ( C₄H₉Cl ) to be optically active, it must have a chiral center. P ( C₄H₈ ) = but-2-ene ( CH₃-CH=CH-CH₃ ) P + HCl → Q: CH₃-CH=CH-CH₃ + HCl CH₃-CH(Cl)-CH₂-CH₃ (2-chlorobutane, chiral at C-2) Q + NH₃ → R: 2-chlorobutane + NH₃ CH₃-CH(NH₂)-CH₂-CH₃ (2-aminobutane) R → diazotization → hydrolysis → S: 2-aminobutane NaNO₂/HCl diazonium salt H₂O CH₃-CH(OH)-CH₂-CH₃ (butan-2-ol)

A hydrocarbon ' P ^ ( C ₄ H ₈ ) on reaction with HCl gives an optically active compound ' Q ' ( C ₄ H ₉ Cl ) which on reaction with one mole of ammonia gives compound ' R ^ ( C ₄ H ₁₁ ~N ) . ' R ^ on diazotization followed by hydrolysis gives ' S '. Identify P , Q , R and S.

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