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JEE Main 202621 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
21 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Amines

JEE Main 2026 · 21 January · Morning Shift · Chemistry · Amines

A hydrocarbon ' P^ (C_ 4 H_ 8 ) on reaction with HCl gives an...

A hydrocarbon ' P′(C4H8)\mathrm{P}^{\prime}\left(\mathrm{C}_{4} \mathrm{H}_{8}\right) on reaction with HCl gives an optically active compound ' Q ' \left(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{Cl}\right)whichonreactionwithonemoleofammoniagivescompound′which on reaction with one mole of ammonia gives compound '\mathrm{R}^{\prime}\left(\mathrm{C}_{4} \mathrm{H}_{11} \mathrm{~N}\right).′. '\mathrm{R}^{\prime}ondiazotizationfollowedbyhydrolysisgives′S′.<br>Identifyon diazotization followed by hydrolysis gives ' S '.<br>Identify\mathrm{P}, \mathrm{Q}, \mathrm{R} and S.A hydrocarbon ' P^ (C_ 4 H_ 8 ) on reaction with HCl gives an optically active compound ' Q ' (C_ 4 H_ 9 Cl) which onA hydrocarbon ' P^ (C_ 4 H_ 8 ) on reaction with HCl gives an optically active compound ' Q ' (C_ 4 H_ 9 Cl) which onA hydrocarbon ' P^ (C_ 4 H_ 8 ) on reaction with HCl gives an optically active compound ' Q ' (C_ 4 H_ 9 Cl) which onA hydrocarbon ' P^ (C_ 4 H_ 8 ) on reaction with HCl gives an optically active compound ' Q ' (C_ 4 H_ 9 Cl) which on

Options

  1. ALet the function f(x)=(x)/(3)+(3)/(x)+3, x ≠ 0 be strictly increasing in (-∞, α_1) U(α_2, ∞) and strictly decreasing in
  2. BLet the function f(x)=(x)/(3)+(3)/(x)+3, x ≠ 0 be strictly increasing in (-∞, α_1) U(α_2, ∞) and strictly decreasing in
  3. CLet the function f(x)=(x)/(3)+(3)/(x)+3, x ≠ 0 be strictly increasing in (-∞, α_1) U(α_2, ∞) and strictly decreasing in
  4. DLet the function f(x)=(x)/(3)+(3)/(x)+3, x ≠ 0 be strictly increasing in (-∞, α_1) U(α_2, ∞) and strictly decreasing in

Correct answer

D. Let the function f(x)=(x)/(3)+(3)/(x)+3, x ≠ 0 be strictly increasing in (-∞, α_1) U(α_2, ∞) and strictly decreasing in

Step-by-step solution

For Q (C4H9ClC_4H_9Cl) to be optically active, it must have a chiral center.
P (C4H8C_4H_8) = but-2-ene (CH3−CH=CH−CH3CH_3-CH=CH-CH_3)
P + HCl → Q: CH3−CH=CH−CH3+HCl→CH3−CH(Cl)−CH2−CH3CH_3-CH=CH-CH_3 + HCl \rightarrow CH_3-CH(Cl)-CH_2-CH_3 (2-chlorobutane, chiral at C-2)
Q + NH3NH_3 → R: 2-chlorobutane + NH3→CH3−CH(NH2)−CH2−CH3NH_3 \rightarrow CH_3-CH(NH_2)-CH_2-CH_3 (2-aminobutane)
R → diazotization → hydrolysis → S: 2-aminobutane →NaNO2/HCl\xrightarrow{NaNO_2/HCl} diazonium salt →H2O\xrightarrow{H_2O} CH3−CH(OH)−CH2−CH3CH_3-CH(OH)-CH_2-CH_3 (butan-2-ol)
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