When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K) and acidified with acetic acid, the mass ( g) of 0.1 mole of product formed is :
(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14$ , $\mathrm{O}: 16, \mathrm{~S}: 32)$

Question

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K) and acidified with acetic acid, the mass ( g) of 0.1 mole of product formed is :
(Given molar mass in

\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14

,

\mathrm{O}: 16, \mathrm{~S}: 32)

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K) and

Quantrex Academy · Accepted Answer

Correct answer: C. 33

0.1 mole of red-azo dye ( Molar Mass =327 gm / mol) will have 32.7 gm mass. Nearly 33 gm.

When a concentrated solution of sulphanilic acid and...

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