When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K) and acidified with acetic acid, the mass ( g) of 0.1 mole of product formed is : (Given molar mass in g mol ⁻¹ H : 1, C : 12, ~N : 14

Question

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K) and acidified with acetic acid, the mass ( g) of 0.1 mole of product formed is : (Given molar mass in g mol ⁻¹ H : 1, C : 12, ~N : 14 , O : 16, ~S : 32)

Quantrex Academy · Accepted Answer

Correct answer: C. 33

0.1 mole of red-azo dye ( Molar Mass =327 gm / mol ) will have 32.7 gm mass. Nearly 33 gm.

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K) and acidified with acetic acid, the mass ( g) of 0.1 mole of product formed is : (Given molar mass in g mol ⁻¹ H : 1, C : 12, ~N : 14 , O : 16, ~S : 32)

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