A reaction of 0.1 mole of Benzylamine with bromomethane gave $23g$ of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are $n \times {10}^{- 1},$ when $n =$ _____ (Round off to the Nearest Integer).
$\left(\text{Given : Atomic masses}: C: 12 . 0u, H: 1 . 0u, N: 14 . 0u, Br: 80 . 0u\right)$

Question

A reaction of 0.1 mole of Benzylamine with bromomethane gave

23g

of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are

n \times {10}^{- 1},

when

n =

_____ (Round off to the Nearest Integer).

\left(\text{Given : Atomic masses}: C: 12 . 0u, H: 1 . 0u, N: 14 . 0u, Br: 80 . 0u\right)

Quantrex Academy · Accepted Answer

Correct answer: 0

no of moles = 3 × 10 ^ - 1 mol

A reaction of 0.1 mole of Benzylamine with bromomethane gave 23g of...