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JEE Main 202124 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
24 February
Shift
Evening Shift
Subject
Chemistry
Chapter
Amines

JEE Main 2021 · 24 February · Evening Shift · Chemistry · Amines

The diazonium salt of which of the following compounds will form a...

The diazonium salt of which of the following compounds will form a coloured dye on reaction with β\beta-Naphthol in NaOH?NaOH ?The diazonium salt of which of the following compounds will form a coloured dye on reaction with β -Naphthol in NaOH ?The diazonium salt of which of the following compounds will form a coloured dye on reaction with β -Naphthol in NaOH ?The diazonium salt of which of the following compounds will form a coloured dye on reaction with β -Naphthol in NaOH ?The diazonium salt of which of the following compounds will form a coloured dye on reaction with β -Naphthol in NaOH ?The diazonium salt of which of the following compounds will form a coloured dye on reaction with β -Naphthol in NaOH ?

Options

  1. AParagraph: Let f(x) be a function satisfying f(x+y)=f(x) f(y) for all x, y∈ ℕ such that f(1)=2 : Question: What is ∑_
  2. BParagraph: Let f(x) be a function satisfying f(x+y)=f(x) f(y) for all x, y∈ ℕ such that f(1)=2 : Question: What is ∑_
  3. CParagraph: Let f(x) be a function satisfying f(x+y)=f(x) f(y) for all x, y∈ ℕ such that f(1)=2 : Question: What is ∑_
  4. DParagraph: Let f(x) be a function satisfying f(x+y)=f(x) f(y) for all x, y∈ ℕ such that f(1)=2 : Question: What is ∑_

Correct answer

B. Paragraph: Let f(x) be a function satisfying f(x+y)=f(x) f(y) for all x, y∈ ℕ such that f(1)=2 : Question: What is ∑_

Step-by-step solution

The colour obtained is the colour of the compound formed in the reaction of aniline with NaNO2/HCl{NaNO}_{2} / HCl at 0oC{0}^{o}C followed by coupling with β-naphthol.

Aniline on reaction withNaNO2/HCl{NaNO}_{2} / HCl forms a diazonium salt. This diazonium salt is then coupled with β-naphthol.

The diazonium salt of which of the following compounds will form a coloured dye on reaction with β -Naphthol in NaOH ?

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