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JEE Main 20199 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
9 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Amines

JEE Main 2019 · 9 April · Morning Shift · Chemistry · Amines

Aniline dissolved in dilute HCl is reacted with sodium nitrite at 0...

Aniline dissolved in dilute HClHCl is reacted with sodium nitrite at 0°C0 ° C. This solution was added dropwise to a solution containing an equimolar mixture of aniline and phenol in dilute HClHCl. The structure of the major product isAniline dissolved in dilute HCl is reacted with sodium nitrite at 0 ° C . This solution was added dropwise to aAniline dissolved in dilute HCl is reacted with sodium nitrite at 0 ° C . This solution was added dropwise to aAniline dissolved in dilute HCl is reacted with sodium nitrite at 0 ° C . This solution was added dropwise to aAniline dissolved in dilute HCl is reacted with sodium nitrite at 0 ° C . This solution was added dropwise to aAniline dissolved in dilute HCl is reacted with sodium nitrite at 0 ° C . This solution was added dropwise to a

Options

  1. AWhen two progressive waves y_1=4 (2 x-6 t) and y_2=3 (2 x-6 t-(π)/(2)) are superimposed, the amplitude of the resultant
  2. BWhen two progressive waves y_1=4 (2 x-6 t) and y_2=3 (2 x-6 t-(π)/(2)) are superimposed, the amplitude of the resultant
  3. CWhen two progressive waves y_1=4 (2 x-6 t) and y_2=3 (2 x-6 t-(π)/(2)) are superimposed, the amplitude of the resultant
  4. DWhen two progressive waves y_1=4 (2 x-6 t) and y_2=3 (2 x-6 t-(π)/(2)) are superimposed, the amplitude of the resultant

Correct answer

A. When two progressive waves y_1=4 (2 x-6 t) and y_2=3 (2 x-6 t-(π)/(2)) are superimposed, the amplitude of the resultant

Step-by-step solution

Aniline dissolved in dilute HCl is reacted with sodium nitrite at 0 ° C . This solution was added dropwise to a
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